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| CrashNBurn | Posted on: 9/22/2011 3:37 pm |
Just can't stay away ![]() ![]() Joined: 4/8/2010 From: Posts: 130 |
Re: Ignore \r in regex The (? syntax is something entirely different.
Example, given the following Text Quote: This is a test sentence Try this regex: Search: ^(.*)(?|(a test )|(a regex ))(.*)$ Replace: \3 With the (?| syntax, there will only be 3 pieces, since the section inside (?|...) isn't counted as a bracket set. For the first line: \1: This is_ \2: a test_ \3: sentence The lines will be replaced with "sentence" and "string". Now without the (?| syntax, eg: Search: ^(.*)((a test )|(a regex ))(.*)$ that regex would contain 5 pieces that would be matched with \1 thru \5, and some of them would be empty, depending on the line. For the first line: \1: This is_ \2: a test_ \3: a test_ \4: \5: sentence The (? syntax becomes important if you utilize more complex regexes due to the nature of regex to match everything it absolutely can when things like ".*" are present. Example 2A: Search: ^(.*)( is a | a regex )? Replace: \1_ That regex will match the whole line, and the replace wont change anything -- as the .* consumes the whole line, since the part in (brackets)? is optional, the greedy regex wont see it. Example 2B: Search: ^(.*)(?|( is a )|( a regex )) Replace: \1_ This regex will actually remove " is a " and " a regex " from the lines in question. A lot of editors don't even implement the full regex spec, e.g. Notepad2 does a small subset which doesn't even handle the optional "?" correctly, and certainly doesn't support the (?| syntax. |
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Deipotent | 8/24/2011 9:10 am |
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Stefan | 8/24/2011 12:02 pm |
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Deipotent | 8/24/2011 5:08 pm |
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CrashNBurn | 9/22/2011 3:37 pm |
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