February 4, 2009 at 7:22 am #6884
spectre
Member
Thank you for the clarification.
I probably did not explain my point right. Let’s consider a following example.
Assume we have a solution, say, D:xworksamplesmy_solution.eesln
$(Solution) gives
D:xworksamplesmy_solution.eesln
as it should.
I tried $(Solution,f) and it gave
D:xworksamplesmy_solution
But what I would like to have is just
my_solution
That is, just file name, no path.
I mostly need this to construct the paths like the following:
D:xworksamplesdebugmy_solution.smth
( $(Solution,d)debug$(Solution,).smth )